Question

is this possible
$(x + 1) \div (3 {x}^{2} + x + 1)$
​

Answer 1

Step-by-step explanation:

g(x)=x+1

x+1=0

x=0-1x=-1

p(x)=3x^2+x+1

p(-1)=3(-1)^2+(-1)+1

=(3×1)-1+1

=3-0

=3

Answer 2

Answer:

x

2

−x+1 will be a factor of x

3

−3x

2

+3x−2 when the remainder is zero.

Dividing x

3

−3x

2

+3x−2 by x

2

−x+1, as shown in the figure. We get:

Quotient as x−2.

and Remainder as 0.

Since the remainder is 0, x

2

−x+1 is a factor of x

3

−3x

2

+3x−2.