Question

is this question in boards 2021....please let me know... ​

Answer 1

Given that,

sin∅ + cos∅ = √2cos(90 - ∅)

We know that, cos(90 - ∅) = sin∅

Further,

$\longrightarrow$ sin∅ + cos∅ = √2sin∅

$\longrightarrow$ cos∅ = √2sin∅ - sin∅

$\longrightarrow$ cos∅ = sin∅(√2 - 1)

$\longrightarrow$ cos∅/sin∅ = √2 - 1

$\longrightarrow$ cot∅ = √2 - 1

$\longrightarrow$ cot∅ = 1.41 - 1

$\longrightarrow$ cot∅ ≈ 0.41

Therefore, the value of cot∅ is √2 - 1.

Answer 2

Given that,

$sin∅ + cos∅ = √2cos(90 - ∅)$

We know that,

$cos(90 - ∅) = sin∅$

Further,

$⟶ sin∅ + cos∅ = √2sin∅$

$⟶ cos∅ = √2sin∅ - sin∅$

$⟶ cos∅ = sin∅(√2 - 1)$

$⟶ cos∅/sin∅ = √2 - 1$

$⟶ cot∅ = √2 - 1$

$⟶ cot∅ = 1.41 - 1$

$⟶ cot∅ ≈ 0.41$

Therefore,

The value of

$cot∅ \: is \: √2 - 1.$