Is this right? Lets say we are solving 1604 - 8 * When subtracting a greater number in an n^x value place that is greater than the n^x place, (in this case x is 1,) you have to minus one from the greater place value; (n^x+1) which the sum of the equation (n^x+1) is n^2 which would be the tens column. From that now you add 10 ones (i think) to the ones place. In other words, when subtracting 8 from 2 or something like that, you would have to first count from ones down until you have no ones then subtract a tens from the tens column then add 10 ones to the ones place but if there is a sum like 1088 - 8 you should not do that but instead add 0 ones but subtract one ten, but back to what i was saying. So then after adding 10 ones keep subtracting down until you are done. Then that's how I got my answer.
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