Question

is this sum correct please tell​

Answer 1

$4x(x - 1) - (2x - 5) = 4$

=> 4x²-4x -2x +5=4

=> 4x²-6x +5=4

=> 4x²-6x+5-4 = 0

=> 4x²-6x+1=0

$= > x = \frac{ - ( - 6)± \sqrt{ ( { - 6)}^{2} } - 4.4.1}{2.4} \\ \\ seperate \:the \: equation = > x = \frac{6± 2 \sqrt{5} }{8} \\ = > x = \frac{6 + 2 \sqrt{5} }{8} \\ x = \frac{6 - 2 \sqrt{5} }{8} \\ now \\ x = \frac{3 + \sqrt{5} }{4} \\ x = \frac{3 - \sqrt{5} }{4}$

$solution$

$x = \frac{3± \sqrt{5} }{4}$

Answer 2

4x(x−1)−(2x−5)=4

=> 4x²-4x -2x +5=4

=> 4x²-6x +5=4

=> 4x²-6x+5-4 = 0

=> 4x²-6x+1=0

\begin{gathered} = > x = \frac{ - ( - 6)± \sqrt{ ( { - 6)}^{2} } - 4.4.1}{2.4} \\ \\ seperate \:the \: equation = > x = \frac{6± 2 \sqrt{5} }{8} \\ = > x = \frac{6 + 2 \sqrt{5} }{8} \\ x = \frac{6 - 2 \sqrt{5} }{8} \\ now \\ x = \frac{3 + \sqrt{5} }{4} \\ x = \frac{3 - \sqrt{5} }{4} \end{gathered}

=>x=

2.4

−(−6)±

(−6)

2

−4.4.1

seperatetheequation=>x=

8

6±2

5

=>x=

8

6+2

5

x=

8

6−2

5

now

x=

4

3+

5

x=

4

3−

5

solutionsolution

x = \frac{3± \sqrt{5} }{4}x=

4

3±

5