Question

is two years older than B who is twice as old as C if the total of the ages is 27 how old is B

Answer 1

The age of B is 9 years

Answer 2

Let the present age of C is x years ,

Therefore,
Age of B = twice of C = 2x years
Age of A = 2 years more than age of B = ( 2x + 2 ) years



Given, total of the ages = 27

Age of A + age of B + age of C = 27

2x + 2 + 2x + x = 27

2x + 2x + x + 2 = 27

5x + 2 = 27

5x = 27 - 2

5x = 25

x = 25 / 5

x = 5




Thus,
Age of B = 2x years = 2( 5 ) years = 10 years.


Hence, age of B is 10 years
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