Question

Is (x+1)² = 2(x+3) is quadratic equation. or not​

Answer 1

$\sf\huge {\underline{\underline{{Solution}}}}$

Firstly know what is quadratic equation :

A quadratic equation which is in the form of ax²+bx+c and where a ≠ 0 , if equals then the Equation be a linear or non-quadratic .

=> (x+1)²= 2(x+3)

opening the brackets and expanding the terms:

Identity : (a+b)²= a²+b²+2ab

=> x²+1²+2(x)(1)= 2x+6

=> x²+1+2x= 2x+6

2x lies on both sides so, it gets cancelled:

=> x²+1= 6

=> x²+1-6

=> x²-5

Here, x²-5 in accordance with ax²+bx+c

x term is missing so,it does not form the quadratic equation.

Therefore, (x+1)²= 2(x+3) is not a quadratic equation.

Answer 2

$\huge \mathfrak{ solution}$

Firstly know what is quadratic equation :

A quadratic equation which is in the form of ax²+bx+c and where a ≠ 0 , if equals then the Equation be a linear or non-quadratic .

=> (x+1)²= 2(x+3)

opening the brackets and expanding the terms:

Identity : (a+b)²= a²+b²+2ab

=> x²+1²+2(x)(1)= 2x+6

=> x²+1+2x= 2x+6

2x lies on both sides so, it gets cancelled:

=> x²+1= 6

=> x²+1-Firstly know what is quadratic equation :

A quadratic equation which is in the form of ax²+bx+c and where a ≠ 0 , if equals then the Equation be a linear or non-quadratic .

=> (x+1)²= 2(x+3)

opening the brackets and expanding the terms:

Identity : (a+b)²= a²+b²+2ab

=> x²+1²+2(x)(1)= 2x+6

=> x²+1+2x= 2x+6

2x lies on both sides so, it gets cancelled:

=> x²+1= 6

=> x²+1-6

=> x²-5

Here, x²-5 in accordance with ax²+bx+c

x term is missing so,it does not form the quadratic equation.

Therefore, (x+1)²= 2(x+3) is not a quadratic equation. equation.

Therefore, (x+1)²= 2(x+3) is not a quadratic equation.

$\huge {thank \: you}$