Question

is (x+1) a factor of xcube + x square + x + 1​

Answer 1

Answer:

Here is your answer !!

↪To check that (x + 1) is the factor we will put value of x in the given polynomial .

↪Hence ,

↪x + 1 = 0

↪x = -1

↪p ( x ) = x ^3 + x ^2 + x + 1

↪( -1 )^3 + ( -1 )^2 + ( -1 ) + 1 = 0

↪- 1 + 1 - 1 + 1 = 0

↪0 = 0

↪Hence zero is the required answer

↪( x + 1 ) is the factor of given polynomial.