is x=-1 a root of the quatratic equation x2-3x-4=0?
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Step-by-step explanation:
Take x=1 in equation
x²-3x-4=0
1²-3(1)-4
1-3-4
=1-(-7)
=1+8=9
That is not equal to 0
Answered by
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x²-3x-4=0
x²-4x+x-4=0
x(x-4) + 1(x-4)=0
(x+1) (x-4) =0
(x+1)=0 (x-4)=0
x=-1 or x=4
Therefore,x=-1 is a root of quadratic equation x²-3x-4=0.
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