Math, asked by abhi6908, 2 months ago

Is (x+1) is a factor of the polynomial x^1002 +x^923+x^856+x^177-x^29+1?​

Answers

Answered by lovemyself78
0

x + 1) is the factor of the polynomial P(x):x^{997}+x^{886}+x^{775}+x^{654}+x^{113}+1P(x):x

997

+x

886

+x

775

+x

654

+x

113

+1 , proved.

Step-by-step explanation:

Given,

(x + 1) is the factor of the polynomial P(x):x^{997}+x^{886}+x^{775}+x^{654}+x^{113}+1P(x):x

997

+x

886

+x

775

+x

654

+x

113

+1

To prove that, (x + 1) is the factor of the polynomial P(x):x^{997}+x^{886}+x^{775}+x^{654}+x^{113}+1P(x):x

997

+x

886

+x

775

+x

654

+x

113

+1 .

∵ x + 1 = 0

⇒ x = - 1

Put x = - 1 in P(x), we get

P(-1)=(-1)^{997}+(-1)^{886}+(-1)^{775}+(-1)^{654}+(-1)^{113}+1P(−1)=(−1)

997

+(−1)

886

+(−1)

775

+(−1)

654

+(−1)

113

+1

= - 1 + 1 - 1 + 1 - 1 + 1

= 3 - 3

= 0, proved.

Thus, (x + 1) is the factor of the polynomial P(x):x^{997}+x^{886}+x^{775}+x^{654}+x^{113}+1P(x):x

997

+x

886

+x

775

+x

654

+x

113

+1 , proved.

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