Question

is (x+1)(x+3)=(x-1)(x-4) a quadratic equation?​
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Answer 1

Step-by-step explanation:

Given

$(x + 1)(x + 3) = (x - 1)(x - 4)$

${x}^{2} + 4x + 3 = {x}^{2} - 5x + 4$

$9x - 1 = 0$

Since the square term has been cancelled out, so the given equation is not a Quadratic equation.

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Answer 2

Given

(x + 1)(x + 3) = (x - 1)(x - 4)(x+1)(x+3)=(x−1)(x−4)

${x}^{2} + 4x + 3 = {x}^{2} - 5x + 4x$

9x - 1 = 0

Since the square term has been cancelled out, so the given equation is not a Quadratic equation.