Question

is (x+2) a factor of 4x^4+2x^3-3x^2+8x-20​

Answer 1

Answer:

Yes

Step-by-step explanation:

Let f(x) = 4x^4+2x^3-3x^2+8x-20 be the given polynomial

if From factor theorem if (x+2) is a factor of f(x) then f(-2) = 0

therefore,

f(-2)= 4(-2)^4+2(-2)^3-3(-2)^2+8(-2)-20

=4(16)+2(-8)-3(4)-16-20

=64-16-12-16-20

=64-64

=0

therefore (x+2) is a factor of 4x^4+2x^3-3x^2+8x-20.

Answer 2

Answer:

0

Step-by-step explanation:

p(x) => 4x^4+2x^3-3x^2+8x-20

(x+2)=0

x= -2

therefore, p(-2) => 4(-2)^4+2(-2)^3-3(-2)^2+8(-2)-20

=> (16×4)+(2×-8)-(3×4)-16-20

=> 64-16-12-16-20

=> 64-64

=> 0