Question

is (,x-3) (2x+1)=x(x+5) a quadratic equation​

Answer 1

Answer:

is not quadratic equation.................

Answer 2

$\huge\mathfrak\green{Answer}$

$(x-3)(2x+1)=x(x+5) \\ = 2x^{2}-5x-3=x\left(x+5\right) \\ = 2x^{2}-5x-3=x^{2}+5x \\ = 2x^{2}-5x-3-x^{2}=5x \\ = x^{2}-5x-3=5x \\ = x^{2}-5x-3-5x=0 \\ = x^{2}-10x-3=0 \\ = x=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}-4\left(-3\right)}}{2} \\ = x=\frac{-\left(-10\right)±\sqrt{100-4\left(-3\right)}}{2} \\ = x=\frac{-\left(-10\right)±\sqrt{100+12}}{2} \\ = x=\frac{-\left(-10\right)±\sqrt{112}}{2} \\ = x=\frac{-\left(-10\right)±4\sqrt{7}}{2} \\ = x=\frac{10±4\sqrt{7}}{2} \\ = x=\frac{4\sqrt{7}+10}{2} \\ = x=2\sqrt{7}+5 \\ = x=\frac{10-4\sqrt{7}}{2} \\ = x=5-2\sqrt{7} \\ = x=2\sqrt{7}+5 x \\ = x=5-2\sqrt{7}$