Is {x R : x2 + x + 1 = 0} a empty set? Justify your answer
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Step-by-step explanation:
Given,
X² + x + 1 = 0
x² + 1² +x
( x + 1)² - 2x + x
( x + 1)² - x
hence,
the given set Contained some elements so, it is not empty or null set
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