Math, asked by rishit200645, 9 months ago

is x2 - 1 a multiple of (x-1)​

Answers

Answered by Anonymous
2

Answer:

Yes

Step-by-step explanation:

Given,

x^2 - 1

To find whether (x^2-1) is a multiple of (x-1).

We know that,

If a number 'a' is a multiple of any given number 'b',

Then, 'a' must comes in table of 'b'.

Or, we can say that,

'a' is m times b, i.e.,

=> a = mb

Where, m is any real number.

Now, we have,

x^2 - 1

= (x+1)(x-1)

= m(x-1)

Where, m = (x+1)

Clearly, it satisfies the required conditions.

Hence, (x^2 - 1) is a multiple of (x-1).

Answered by girikbhandoria
0

Answer:

Given,

x^2 - 1

To find whether (x^2-1) is a multiple of (x-1).

We know that,

If a number 'a' is a multiple of any given number 'b',

Then, 'a' must comes in table of 'b'.

Or, we can say that,

'a' is m times b, i.e.,

=> a = mb

Where, m is any real number.

Now, we have,

x^2 - 1

= (x+1)(x-1)

= m(x-1)

Where, m = (x+1)

Clearly, it satisfies the required conditions.

Hence, (x^2 - 1) is a multiple of (x-1).

Step-by-step explanation:

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