Is (x²)² + 2√5 polynominals
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Answer:
expanding we get,
x⁴ - 2 × x² × √2 + 2 = 2
Cancel 2 on both sides,
x⁴ − 2 × x² × √2 = 0
Take the common factor outside,
x²( x² − 2√2 ) = 0
=> x² = 0 Or x² − 2√2 = 0
=> x =0 Or x² = 2√2
=> x = 0 Or x² = 2.82842712474619
=> x = 0 Or x = √2.82842712474619
NO
shrutikeshri09:
wts wrong in wishing
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