Math, asked by prantarudra999, 3 months ago


Is y(x) = 1 a solution of y"+2y'+y=
x?​

Answers

Answered by gayatrip958
0

Answer:

Step-by-step solutions for differential equations : separable equations, Bernoulli ... y'(t) - 2y(t) = 3 e^(2t) · x y'(x) - 4 y(x) = x^6 exp(x), y(1) = 0.

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