is zero a term of A.p 31,28,25.......?justify your answer
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Answered by
11
a=31 d=28-31=-3
An=a+(n-1)d
0=31+(n-1)-3
-31=-3n+3
-31-3=-3n
-34=-3n
n=34/3
so it is in fraction so no zero is there in this A.P
An=a+(n-1)d
0=31+(n-1)-3
-31=-3n+3
-31-3=-3n
-34=-3n
n=34/3
so it is in fraction so no zero is there in this A.P
Answered by
6
an=0
a=31
d=28-31= -3
an= a+(n-1)d
0= 31+(n-1)(-3)
-31/-3= n-1
31/3 + 1 =n
n = 34/3 which is not a natural number.
so therefore, zero is not a term of given A.P...
I hope this answer is helpful to u....
a=31
d=28-31= -3
an= a+(n-1)d
0= 31+(n-1)(-3)
-31/-3= n-1
31/3 + 1 =n
n = 34/3 which is not a natural number.
so therefore, zero is not a term of given A.P...
I hope this answer is helpful to u....
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