इसका आंसर फटाफट ढूंढ के दो
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Given that √3 tanθ = 1
⇒ tanθ = 1∕√3
⇒ tanθ = tan 30°
⇒ θ = 30°
⇒sin²θ - cos²θ = sin²30° - cos²30 = 1∕4-3∕4 = -1∕2
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Given that √3 tanθ = 1
⇒ tanθ = 1∕√3
⇒ tanθ = tan 30°
⇒ θ = 30°
⇒sin²θ - cos²θ = sin²30° - cos²30 = 1∕4-3∕4 = -1∕2
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