Isha has ice-cream in a cylindrical container A having radius of 20 cm and height 14 cm. If she distributed the ice-cream in two cylindrical cups having radius 7 cm and height 5 cm and four cups in the shape of hemisphere having diameter 21 cm. Find the volume of ice-cream does Isha now remain
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Class 10
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>>Surface Areas and Volumes
>>Volume of Combined Solids
>>A cylindrical container of radius 6 cm a
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A cylindrical container of radius 6 cm and height 15 cm is fulled with ice-cream. The whole ice-cream has to be distributed to 10 children in equal cones with hemispherical tops. If the height of the conical portion is four times the radius of its base, find the radius of the ice-cream cone
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Correct option is A)
Given, Radius of cylindrical container =6cm
Height of cylindrical container =15cm
Volume of cylinder =πr
2
h
=π×36×15
=540πcm
3
Now, as it has to be divided among 10 children
∴ Dividing volume by 10=
10
540
=54πcm
3
Volume of cone + Volume of hemispherical top = Volume of ice-cream in it.
⇒
3
1
πr
2
h+
3
2
πr
3
=πr
2
h
⇒
3
1
πr
2
(4r)+
3
2
πr
3
=54π
⇒
3
1
πr
3
(4+2)=54π
⇒2r
3
=54⇒r=3
Hence, the radius of icecream cone =3 cm
Step-by-step explanation:
answer given in picture above