Ishan walks five times around a triangle park of side 351 m,146 m,and 543 m,while shivi walks three times around a square park of sides 525 m who walks more and by how much
Answers
Answer:
Total distance covered by Guru =5× (Perimeter of triangular park)
= 5(351 + 146 + 543)
= 5 times 1040
= 5200
=5(351+146+543)
=5×1040
=5200m
Total distance covered by Balu = 3×(Perimeter of square park).
= 3(4 \times 525)
= 3 \times 2100
= 6300m
=3(4×525)
=3×2100
=6300m
So, we can see that distance covered by Balu is greater than the distance covered by Guru.
Difference between the distances they covered =
+6300 - 5200) m = 1100
(6300−5200)m
=1100m
Thank you =)
Step-by-step explanation:
perimeter of triangle=351+146+543
=1040m
Ishaan walks 5 times so,
1040×5=5200
Ishaan walks 5200m
perimeter of square=525×4
=2100m
ShivI walks 3 times so,
2100×3=6300
shivi walks 6300m
Now we conclude that shivi walks more than Ishaan by (6300-5200) 1100
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