Math, asked by bamnatkhushi, 2 months ago

Ishan walks five times around a triangle park of side 351 m,146 m,and 543 m,while shivi walks three times around a square park of sides 525 m who walks more and by how much ​

Answers

Answered by varsha2oo6
0

Answer:

Total distance covered by Guru =5× (Perimeter of triangular park)

= 5(351 + 146 + 543)

= 5 times 1040

= 5200

=5(351+146+543)

=5×1040

=5200m

Total distance covered by Balu = 3×(Perimeter of square park).

= 3(4 \times 525)

= 3 \times 2100

= 6300m

=3(4×525)

=3×2100

=6300m

So, we can see that distance covered by Balu is greater than the distance covered by Guru.

Difference between the distances they covered =

+6300 - 5200) m = 1100

(6300−5200)m

=1100m

Thank you =)

Answered by janhaviabcd
0

Step-by-step explanation:

perimeter of triangle=351+146+543

=1040m

Ishaan walks 5 times so,

1040×5=5200

Ishaan walks 5200m

perimeter of square=525×4

=2100m

ShivI walks 3 times so,

2100×3=6300

shivi walks 6300m

Now we conclude that shivi walks more than Ishaan by (6300-5200) 1100

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