Question

Ishi applied a force of 20 N on a box of mass 10kg.She found that by applying this force,she was able to double the velocity of the box in 8 s.The initial velocity of the box is: * 1 point 4m/s 8m/s 32 m/s 16 m/s​

Answer 1

Answer:

16m/s

Explanation:

Let V=2U

F=20N

m=10kg

T=8sec

F=m×a

20 =10×a

a=2m/sec^2

V=U+at

2U=U+at

U=2×8=16m/sec

Last Option:-16m/sec

Answer 2

Answer:

Initial velocity fo the object = 16m/s

Explanation:

let us first write all the givenr unit then it will become a bit easier for us :-

force = 20N

mass = 10kg

initial velocity = u

final velocity = 2u ( because Ishi was able to double it's velocity )

time = 8s

Now, first we will find out the acceleration

v = u + at

2u = u + a(8) [ By putting the values ]

2u = u + 8a

u + 8a = 2u

8a = 2u - u

8a = u

a = $\frac{u}{8}$

Now. we will put this into the formula of force

F = ma

20 = 10 * $\frac{u}{8}$

20 = 5 * $\frac{u}{4}$

$\frac{u}{4} = \frac{20}{5}$

$\frac{u}{4} = 4$

u = 4 * 4

u = 16m/s

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Thank you :-)