Isides of triangles are 63cm ,65cm,16cm .find the area of this triangle
Answers
Answered by
5
Step-by-step explanation:
Let base BC=a=63cm, hypo AC=b=65cm.and perpendicular AB= 16cm cm of right angled triangle ABC.
s=(63+65+16)/2=144/2=72cm.
Area=[s.(s-a) (s-b) (s-c)]^1/2.
=[72(72–63)(72–65)(72–16)]^1/2.
=[72×9×7×56]^1/2.
=[8×9×9×7×7×8]^1/2.
=7×8×9 cm^2.
=504 sq.cm. . Answer.
Answered by
0
Answer:
504 cm²
Step-by-step explanation:
- use herons formula to find the area
- hope it helps
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