Question

iska answer bata do bhai jaldi se​

Answer 1

Step-by-step explanation:

We have,

$\frac{ \sec( \theta) - \tan(\theta) + 1 }{ \sec(\theta) + \tan(\theta) + 1 }$

$= \frac{ \sec( \theta) - \tan(\theta) + \sec^{2} ( \theta) - \tan^{2} ( \theta) }{ \sec(\theta) + \tan(\theta) + 1 }$

$= \frac{ \sec( \theta) - \tan(\theta) + ( \sec ( \theta) - \tan( \theta) )( \sec( \theta) + \tan( \theta) ) }{ \sec(\theta) + \tan(\theta) + 1 }$

$= \frac{ (\sec( \theta) - \tan(\theta) ) ( \sec( \theta) + \tan( \theta) + 1 ) }{ \sec(\theta) + \tan(\theta) + 1 }$

$= \sec( \theta) - \tan( \theta)$

$= \frac{1 - \sin( \theta) }{ \cos( \theta) }$