Question

iska answer bolo yaar please ... ​

Answer 1

Answer:

2) Let the numbers a^2a

2

and b^2b

2

The total numbers are n=a+b-1n=a+b−1

Where, a=99 and b=100

then, n=a+b-1n=a+b−1

n=99+100-1n=99+100−1

n=199-1n=199−1

n=198n=198