Question

iska answer hai
$(2y - 1)(2y - 3)$
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Answer 1

Solution:-

$4 {y}^{2} - 8y + 3$

$= 4 {y}^{2} - (6 + 2)y + 3$

$= 4 {y}^{2} - 6y - 2y + 3$

$= 2y(2y - 3) - 1(2y - 3)$

$= (2y - 1)(2y - 3)$

Some useful identities:-

${a}^{2} - {b}^{2} = (a + b)(a - b)$

${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab$

${(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab$

${a}^{3} + {b}^{3} = (a + b)( {a}^{2} + {b}^{2} + ab)$

${a}^{3} - {b}^{3} = (a + b)( {a}^{2} + {b}^{2} - ab)$