Question

iska b2 3 4 bta so please
bhaiya didi jisko b aata h but please direct mat bhejna
solve karke please please bhej do​ please

Answer 1

$\large{\tt2.}$

${x}^{2} + x - 6$

${x}^{2} + 3x - 2x - 6 = 0$

$x(x + 3) - 2(x + 3) = 0$

$(x - 2)(x + 3) = 0$

$\orange{x = 2 \: \: \: (or) \: \: \: - 3}$

$\large \tt 3.$

${x}^{2} + 5x + 6$

${x}^{2} + 2x + 3x + 6 = 0$

$x(x + 2)3(x + 2) = 0$

$(x + 2)(x + 3) = 0$

$\orange{x = - 2 \: \: \: (or) \: \: \: - 3}$

$\large \tt 4.$

$- 7 {x}^{2} - 14x + 56$

$- 7 {x}^{2} - 28x + 14x + 56 = 0$

$- 7x(x + 4)4(x + 4) = 0$

$( - 7x + 4)(x + 4) = 0$

$\orange{x = \frac{4}{7} \: \: \: \: (or) \: \: \: - 4 }$

HOPE THIS HELPS!!

Answer 2

Answer:

Step-by-step explanation:

1.x²+6x+8

=x²+4x+2x+8

=x(x+4)+2(x+4)

=(x+4)(x+2)

***********************

2.x²+x-6

x²+3x-2x-6

=x(x+3)-2(x+3)

=(x+3)(x-2)

************************

3.x²+5x+6

=x²+3x+2x+8

=x(x+3)+2(x+3)

=(x+3)(x+2)

*************************

4.  -7x²-14x+56

= -7(x²-2x-8)

= - 7( x²-4x+2x-8)

=-7( x(x-4)+2(x-4))

=  - 7(x-4)(x+2)

IS this not the solution