Question

Isko solve kro yar...​

Answer 1

Step-by-step explanation:

Let angle tetha be equal to angle a.

$LHS = \frac{ \sin(a) }{1 + \cos(a) } + \frac{1 + \cos(a) }{ \sin(a) }$

$= > \frac{ \sin(a) \times \sin(a) + (1 + \cos(a) ) \times (1 + \cos(a)) }{(1 + \cos(a) ) \sin(a) }$

$= > \frac{ {sin}^{2}(a) + {(1 + \cos(a)) }^{2} }{(1 + \cos(a) ) \sin(a) }$

$= > \frac{ {sin}^{2} (a) + 1 + 2 \cos(a) + {cos}^{2}(a) }{( 1 + \cos(a) ) \sin(a) }$

$= > \frac{2 + 2 \cos(a) }{(1 + \cos(a) )\sin(a) } \\ ( { \sin }^{2} (a) + {cos}^{2} (a) = 1)$

$= > \frac{2(1 + \cos(a) )}{(1 + \cos(a) \sin(a) ) } \\ ((1 + \cos(a)) \: cancels \: and\: \frac{1}{ \sin(a) } = \csc(a) )$

=2Cosec (a)

=RHS.

Answer 2

Answer:

Hey mate thank you so much for following me...

Step-by-step explanation:

bye take care... have a great day ❣️