ismein aap sirf distance find karke batao mujhe kitna aata hai
Answers
Answer:
Answer
Initial speed of the three-wheeler, u = 36 km/h = 10 m/s
Final speed of the three-wheeler, v = 0 m/s
Time, t = 4 s Mass of the three-wheeler, m = 400 kg
Mass of the driver, m' = 65 kg
Total mass of the system, M = 400 + 65 = 465 kg
Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:
v = u + at
∴ a = v - u / t = 0-10/4 = -2.5 m/s2
The negative sign indicates that the velocity of the three-wheeler is decreasing with time.
Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:
F = Ma = 465 × (–2.5)
= –1162.5 N
The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.
Explanation:
Initial speed of the three-wheeler, u = 36 km/h = 10 m/s
Final speed of the three-wheeler, v = 0 m/s
Time, t = 4 s Mass of the three-wheeler, m = 400 kg
Mass of the driver, m' = 65 kg
Total mass of the system, M = 400 + 65 = 465 kg
Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:
v = u + at
∴ a = v - u / t = 0-10/4 = -2.5 m/s2
The negative sign indicates that the velocity of the three-wheeler is decreasing with time.
Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:
F = Ma = 465 × (–2.5)
= –1162.5 N
The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.
hope this helps.....
❤️❤️❤️9❤️❤️❤️❤️❤️❤️❤️190000❤️❤️❤️❤️❤️❤️❤️