Question

Isoke is solving the quadratic equation by completing the square.

[tex]10x^{2} + 40x – 13 = 0
10x^{2} + 40x = 13
A(x^{2} + 4x) = 13[/tex]

What is the value of A?

Answer 1

Answer:

10

Step-by-step explanation:

Given  

Isoke is solving the quadratic equation by completing the square. $10x^{2} + 40x – 13 = 0 10x^{2} + 40x = 13 A(x^{2} + 4x) = 13$

What is the value of A?

Now the given equation trying to solve by Isoke is

10 x^2 + 40 x – 13 = 0

10 x^2 + 40 x = 13

10(x^2 + 4 x) = 13

So A will be 10, since they have given as

A(x^2 + 4 x) = 13.

So taking out 10 as common factor we get the above equation and A is equal to 10