Math, asked by rudra39048, 23 days ago

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimete​

Answers

Answered by itzbangtanbutterfly
14

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimete

Area of rectangle = Length × breadth

__________________

Given,

120 = 15 × Breadth

120/15 = breadth

8m = breadth 

_________________

Perimeter of rectangle =2(length +breadth)

______________

Perimeter = 2(15 + 8) 

Perimeter = 2 × 23 

Perimeter = 46 m

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Answered by rimpakuila999
0

Answer:

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Step-by-step explanation:

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimete

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________Perimeter of rectangle =2(length +breadth)

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________Perimeter of rectangle =2(length +breadth)______________

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________Perimeter of rectangle =2(length +breadth)______________Perimeter = 2(15 + 8)

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________Perimeter of rectangle =2(length +breadth)______________Perimeter = 2(15 + 8) Perimeter = 2 × 23

Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________Perimeter of rectangle =2(length +breadth)______________Perimeter = 2(15 + 8) Perimeter = 2 × 23 Perimeter = 46 m

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