Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimete
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Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimete
Area of rectangle = Length × breadth
__________________
Given,
120 = 15 × Breadth
120/15 = breadth
8m = breadth
_________________
Perimeter of rectangle =2(length +breadth)
______________
Perimeter = 2(15 + 8)
Perimeter = 2 × 23
Perimeter = 46 m
Answer:
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Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimete
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________Perimeter of rectangle =2(length +breadth)
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________Perimeter of rectangle =2(length +breadth)______________
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________Perimeter of rectangle =2(length +breadth)______________Perimeter = 2(15 + 8)
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________Perimeter of rectangle =2(length +breadth)______________Perimeter = 2(15 + 8) Perimeter = 2 × 23
Isonia is is is years subhash is 30 years agle is 120 sq cm what its perimeteArea of rectangle = Length × breadth__________________Given,120 = 15 × Breadth120/15 = breadth8m = breadth _________________Perimeter of rectangle =2(length +breadth)______________Perimeter = 2(15 + 8) Perimeter = 2 × 23 Perimeter = 46 m