Question

isopropyl alcohol when treated with copper at 575 k forms mcq​

Answer 1

Answer:

isopropyl alcohol when treated with copper at 575 k form PROPANE .

Explanation:

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Answer 2

Isopropyl alcohol when treated with copper at 575 k forms Acetone.

The Dehydrogenation

Alcohol upon reaction with protic acids tends to lose a molecule of water to form alkenes. These reactions are known as dehydrogenation or dehydration of alcohols.

When vapors of isopropyl alcohol is passed over heated copper we get acetone.

It is an example of Dehydrogenation.

Loss of hydrogen is reduction. A molecule of hydrogen is removed.

$\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\mathrm{OH} \stackrel{\text { heated copper }}{\longrightarrow}\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O}+\mathrm{H}_{2}$

Learn more about Dehydrogenation here,

https://brainly.in/question/48347425?msp_poc_exp=1

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