Question

it 10 Newton force pulls a 2kg mass across a horizontal table the acceleration is 4 metre per second square the coefficient of friction between the two surface is​

Answer 1

F = 10N

M = 2kg

a = 4m/s^2

we know that

f = uN

N = mg

F - f = ma

10N - u*4= 4*2

-4u = -2

u = 1/2

u = 0.5

so cofficent of friction = 0.5

Answer 2

Answer:

1m/s^2

Explanation:

f=ma

4*2

8N

for friction= fnet - fma

2N

2=2*a

a=1

therefore acceleration of friction is 1m/s^2