It (2 x 2 3
3 X - 1
12x+3x+2.
is a symmetric matrix, then x
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0
Answer:
A=[
4
2x−3
x+2
x+1
]
Given A
T
=A
⇒[
4
x+2
2x−3
x+1
]=[
4
2x−3
x+2
x+1
]
Both are equal if corresponding elements are equal
⇒2x−3=x+2
⇒2x−x=3+2
⇒x=5
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