Question

it 3x+2y=12andxy=6 find the value of 9x^(2)+4y^(2)

Answer 1

(3x+2y)^2=9x^2+4y^2+2xy
$(x + y) {2} = x {}^{2} + y {}^{2} + 2xy$
12^2=9x^2 4y^2+2×6
144=9x^2+4y^2+12
9x^2+4y^2= 132