Question

(it) 6x2 -√2x-2=0
Solve this quadratic equation by factorisation
Please it is urgent​

Answer 1

Step-by-step explanation:

6x−

x

2

=1

⇒

x

6x

2

−2

=1

⇒6x

2

−2=x

⇒6x

2

−x−2=0

⇒6x

2

−4x+3x−2=0

⇒2x(3x−2)+1(3x−2)=0

Answer 2

Step-by-step explanation:

The two equations can be written as

x

2

(6k+2) + rx +(3k-1) = 0 ...(1)

and x

2

{12k + 4) + px + (6k - 2) = 0. ...(2)

Divide by 2

∴ x

2

(6k+2)+

2

p

x + {3k-1)=0 ...(3)

Comparing (1) and (3), we get r =

2

p

∴ 2r-p = 0.