Question

it a2+b2+c2=ab+bc+ca find the value of a+b/c​

Answer 1

Hope my answer helps you :)

Solution:-

take it as

a2+b2+c2-ab-bc-ca=0

Multiply both sides with 2, we get

2( a2 + b2 + c2 – ab – bc – ca) = 0

2a2 + 2b2 + 2c2 – 2ab – 2bc – 2ca = 0

(a2 – 2ab + b2) + (b2 – 2bc + c2) + (c2 – 2ca + a2) = 0

(a –b)2 + (b – c)2 + (c – a)2 = 0

Since the sum of square is zero then each term should be zero

(a –b)2 = 0,  (b – c)2 = 0, (c – a)2 = 0

(a –b) = 0,  (b – c) = 0, (c – a) = 0

a = b,  b = c, c = a

a = b = c

So (a+b)/c = 2 (Answer)

Thank you :)