Question

it being given that 1 is one of the zeros of polynomial 7 x minus x cube minus 6 find its other zeros​

Answer 1

here is ur ans hope it helps you.

Answer 2

Answer:

Step-by-step explanation:

P(x)=7x-x^3-6=0. [ A.T.Q]

=x^3-7x+6=0

Now,x=1

=> g(x)=x-1.

Now,by long division method/formula

x-1 [x^3+ 0x^2-7x+6] x^2+x-6

+x^3 - x^2

(-) (+)

now, x^2-7x+6

+x^2-x

(-) (+)

now, -6x+6

-6x +6

(+) (-)

Now, ans =0

(x-1) (x^2+x-6)=0

(x-1) (x^2+3x-2x-6)=0

(x-1)[x(x+3)-2(x+3)]=0

=> (x-1) (x-2) (x-3) =0

now, x-1=0

=>x=1

x-2=0

=>x=2

x+3=0

=>x=3

Therefore, The other two zeroes are 2 and -3