Question

it being given that root 2 is equal to 1.414, 3 is equal to 1.7 32, root 5 is equal to 2.2 3610 is equal to 3.1 62 find the value to three places of decimal 2 minus √3 by root 3​

Answer 1

Answer:

Value of the given expression is 0.153

Step-by-step explanation:

Given:

$\sqrt{3}=1.732$

Now,

$\frac{2-\sqrt{3}}{\sqrt{3}}$

$=\frac{2-\sqrt{3}}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}}$

$=\frac{2\sqrt{3}-3}{3}$

$=\frac{2(1.732)-3}{3}$

$=\frac{3.464-3}{3}$

$=\frac{0.464}{3}$

$=0.152666$

$=0.153$

Answer 2

Answer:

0.154

Step-by-step explanation:

We have to find (2 - √3)/√3

                         =(2/√3) - (√3/√3)

                         =(2/√3)-1

we have √2=1.414 , √3=1.732 , √5 = 2.236 , and √10 = 3.162

so,

=(2/√3)-1

=(2/1.732)-1

=1.154 - 1

=0.154