Question

It being given that too is one the of zero of the polynomial x cube minus 4 x square + X + 6 find the other zeros

Answer 1

Answer:

(x+1)(x-2)(x+3).

Step-by-step explanation:

x³ - 4x² + x + 6

Factors of 6 are: 1 ,2 ,3 & 6

So , take (x + 1 = 0)

x = -1

now,

p(x) = (-1)³-4(-1)²+(-1)+6

-1-4-1+6 = -6+6 = 0

x³-3x²-x²+x+6

x³-3x²+x²+x-6

x³-3x²+x²+3x-2x-6

x³-3x²+x(x+3)-2(x+3)

x³-3x²+(x-2)(x+3)

= (x+1)(x-2)(x+3).