It cost rupees 2200 to paint in a curved surface area of a cylindrical vessel 10 metre deep if the rate of painting is rupees 20 per metre square find the inner curved surface area of the vessel and radius of the base and capacity of The vessel
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Here, h = 10 m
(i) Inner curved surface area = Total cost / Cost of painting per m2
= 2200 / 20 m2 = 110 m2 Ans.
(ii) We have, 2πrh = 110
⇒ 2 × 22 / 7 × r × 10 = 110
⇒ r = 110 x 7/ 2 x 22 x 10 = 1.75 m Ans.
(iii) Capacity of the vessel = π r2h
= 22/ 7 × 1.75 × 1.75 × 10 m3 = 96.25 m3
= 96.25 kl Ans. [1 m3 = 1 kl]
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