Question

It cost rupees 2200 to paint the inner curved surface of the cylinder kal vessels 10 mm deep if the cost of painting is at the rate of 20 m m square find 1 inner curved surface area of vessel 2 bradius of the base 3 Capacity city of the base ​

Answer 1

(i) Cost of painting 1m2 area =Rs.20

(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area

(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2

(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area

(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110

(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110⇒r=22×2×10110×7=47=1.75m

(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110⇒r=22×2×10110×7=47=1.75m(iii) Volume of vessel 

(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110⇒r=22×2×10110×7=47=1.75m(iii) Volume of vessel =πr2h=722×1.75×1.75×10

(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110⇒r=22×2×10110×7=47=1.75m(iii) Volume of vessel =πr2h=722×1.75×1.75×10=96.25m3

(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110⇒r=22×2×10110×7=47=1.75m(iii) Volume of vessel =πr2h=722×1.75×1.75×10=96.25m3=96250 litres