Math, asked by 9671601794, 2 months ago

It costs ₹3300 to paint nthe inner curved surface of a 10 m deep well. If the rate cost of

painting is of ₹30 per m2

, find :

(a) inner curved surface area

(b) diameter of the well

(c) capacity of the well.​

Answers

Answered by iVxsoz
2

Answer:

Step-by-step explanation:

Hey there!

To answer your question, lets go over the information given.

First of all, the height of the well is 10m

Also, the total cost of painting is ₹3300

Lastly, the rate cost of the painting ₹30 per 2 square meters .

Lets start with part A. Inner curved surface area = total cost/rate

=3300/30

=110sq.m

Inner curved surface area =2×pie×r×h

2×22/7×r×10=110

r=110×7/10×2×22

r=7/4

Thats part a done. now lets look at part B.

To find the diameter, we need to divide 7 by 4. After that we need to times it by 2.

The answer to that is 3.5.

Now, lets look at the last part (C).

To find it we need to do the following:

=pie×r^2×h

=22/7×7/4×7/4×10

=77×5/4

=96.25 cubic m

1 cubic meter = 1kl

96.25 cubic metres = 96.25kl

Im sorry if this is too confusing but this was the easiest way i could explain. I hope you have a good day :)

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