Math, asked by ravindra41, 20 days ago

It costs `4400 to paint the inner curved surface of a cylindrical vessel 10 cm deep. If the cost of painting is at the rate of `10 per cm2 , then find the (i) Radius of the base (ii) Inner curved surface area (iii) Capacity of the vessel​

Answers

Answered by ajajit9217
8

Answer:

(i)Radius of the base is 7 cm. (ii) inner curved surface area is 440 sq.cm. and (iii) capacity of vessel is 1540 cu.cm.

Step-by-step explanation:

Given:

(i) Total cost of painting of inner curved surface area of a cylindrical vessel = Rs.4400

Cost of painting of 1 sq. cm. area =rs.10

Inner curved surface area= total cost of painting /cost per sq.cm.

                                          = 4400 / 10 = 440 sq.cm.

(ii) Let radius of the base of cylindrical vessel = r cm.

Height ( h) = 10 cm. (given)

Surface area of cylindrical vessel = 2\pirh

                                                440 = 2 × (22 / 7) × r ×10

                                              r = (440 × 7 ) / ( 2 × 22 × 10)

                                               r = 7 cm.

( iii ) Capacity of vessel = \pi r^{2} h

                                       = (22 / 7) × 7^{2} × 10

                                       = 1540 cm^{3}

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