Question

It costs of rupees 2200 to paint inner Curved Surface Area of a cylinder vessel 10m deep. If the cost of painting is at the rate of rs 20 per m2, fnd the

A) radius of base
B) inner CIRVED SURFACE AREA OF VESSELS
C)CAPACITY OF THE VESSEL.

Answer 1

Step-by-step explanation:

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Answer 2

SOLUTION:

Given:

It costs of Rs.2200 to paint the inner curved surface of a cylindrical vessel 10m deep. If the cost of painting is at the rate of Rs.20/m².

Therefore,

⚫Inner curved surface area of the vessel.

Cost of painting;

Inner curved surface area × Rate of paint.

=)2200 =Inner curved surface area× 20

=)Inner curved surface area= 2200/20

=) Inner curved surface area= 110m²

⚫Radius of base:

Let radius of cylinder be r.

Height,(h)= 10m

Curved surface area of cylinder= 110m².

We know that, formula of CSA;

=) 2πrh

$= > 2 \times \frac{22}{7} \times r \times 10 = 110 \\ \\ = > \frac{44}{7} \times r \times 10 = 110 \\ \\ = > \frac{44}{7} \times r = 11 \\ \\ = > r = \frac{11 \times 7}{44} \\ \\ = > r = \frac{77}{44} \\ \\ = > r = 1.75m$

⚫Capacity of the vessel;

Height= 10m

Radius= 1.75m

Therefore,

Volume of the cylinder= πr²h.

$= > \frac{22}{7} \times 1.75 \times 1.75 \times 10 \\ \\ = > \frac{22}{7} \times 30.625 \\ \\ = > \frac{673.75}{7} {m}^{3} \\ \\ = > 96.25 {m}^{3}$

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