It costs Rs 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20 per m2, find
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Answered by
26
Here, h = 10 m
(i) Inner curved surface area = Total cost / Cost of painting per m2
= 2200 / 20 m2 = 110 m2 Ans.
(ii) We have, 2πrh = 110
⇒ 2 × 22 / 7 × r × 10 = 110
⇒ r = 110 x 7/ 2 x 22 x 10 = 1.75 m Ans.
(iii) Capacity of the vessel = π r2h
= 22/ 7 × 1.75 × 1.75 × 10 m3 = 96.25 m3
= 96.25 kl Ans. [1 m3 = 1 kl]
(i) Inner curved surface area = Total cost / Cost of painting per m2
= 2200 / 20 m2 = 110 m2 Ans.
(ii) We have, 2πrh = 110
⇒ 2 × 22 / 7 × r × 10 = 110
⇒ r = 110 x 7/ 2 x 22 x 10 = 1.75 m Ans.
(iii) Capacity of the vessel = π r2h
= 22/ 7 × 1.75 × 1.75 × 10 m3 = 96.25 m3
= 96.25 kl Ans. [1 m3 = 1 kl]
Answered by
6
Answer:
Total cost of point=2200Rs.
cost of point/m
2
=20Rs.
depth of vessel=10m
Inner curved surface area painted=
cost/m
2
totalcost
=
20
2200
=110m
2
Now, 2πrh=110m
2
2×
7
22
×r×10=110
r=
2×22×10
110×7
=1.75m
∴ radius of the base is 1.75m.
capacity of vessel=πr2
h= 7
22×1.75×1.75×10
=96.25m3
Step-by-step explanation:
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