It costs Rs 3300 to paint the inner curved surface area of a 10m deep well.If the rate cost of painting is of Rs 30 per m2 , find : (a) inner curved surface area ; (b) diameter of the well ; (c) capacity of the well
Answers
Height =10m
Total cost of painting =rupes 3300
Rate=ripped 30 per sq.m
Inner curved surface area =total cost/rate
=3300/30
=110sq.m
Inner curved surface area =2×pie×r×h
2×22/7×r×10=110
r=110×7/10×2×22
r=7/4
Diameter,d=7/4×2
=3.5
Volume=pie×r^2×h
=22/7×7/4×7/4×10
=77×5/4
=96.25 cubic m
1 cubic meter = 1kl
96.25 cubic metres =96.25kl
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Answer:
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Step-by-step explanation:
(i) We know that Cost of painting inner curved surface of the vessel = cost of painting per m2 × inner curved surface of vessel
By substituting the values 3300 = 30 × Inner curved surface of vessel
On further calculation Inner curved surface of vessel = 110 m2
(ii) Consider r as the inner radius of the base It is given that depth = 10m
We know that Inner curved surface of vessel = 2 πrh
By substituting the values 110 = 2 × (22/7) × r × 10 So we get r = (110 × 7)/ (2 × 22 × 10) r = 1.75m
(iii) We know that Capacity of the vessel = πr2h
By substituting the values
Capacity of the vessel = (22/7) × (1.75)2 × 10
So we get Capacity of the vessel = 96.25