Question

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Give a chemical test to distinguish between N-methylethanamine and N,N-dimethyl
ethanamine.
Write the reaction for catalytic reduction of nitrobenzene followed by reaction of
product so formed with bromine water.
Out of butan-1-ol and butan-1-amine, which will be more soluble in water and why?​

Answer 1

Answer:

Hi !!...there it is -----

ANSWER

Explanation:

1. ANSWER ----N-methyletahnamine is a secondary amine. When it reacts with benzenesulphonyl chloride, it forms N- Ethyl -N methyl sulphonamide while and N,N-dimethyl etahnanmine is a tertiary amine it does not react with benzenesulphonyl chloride.

Answer 2

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Explanation:

N-methyletahnamine is a secondary amine. When it reacts with benzenesulphonyl chloride, it forms N- Ethyl -N methyl sulphonamide while and N,N-dimethyl etahnanmine is a tertiary amine it does not react with benzenesulphonyl chloride

. (iii) Butan-1-ol Alcohol forms stronger hydrogen bonds with water than formed by amine due to higher electronegativity of O in alcohol than N in amine...

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