Question

it has been observed that ℅S character in Sb-H bond in SbH3 is .5% predict the % s character in the orbital occupies by L.P​

Answer 1

Answer:

the hybridisation of N = sph3

Explanation:

the hybridisation of %s character in SB-H bond in sbh3 is= 5% total %s -character in N -H bond is = 5×3 %= 6%s character in lone pair ....