Question

It has been suggested that for liquids. It has been suggested that for a liquid distributor for is equal to K in which is constant and S is the surface tension and beta is the compressibility show that K is not a dimensional constant. ​

Answer 1

Answer:

I'm sorry I don't know....

Answer 2

Proved that K = M^−1L^4T^2 and K is not a dimensionless constant.

Explanation:

• Surface tension is force per unit length.
• Dimension of Force is M^1L^1 T^−2, divided by length we get the dimensional formula of surface tension is M^1 L^0 T^−2.
• Compressibility is the fractional change in volume per unit increase in pressure.

Dimension of compressibility is M^−1L^1T^2.

[S] = M^1L^0T^−2

[β] = M^−1L^1T^2

S3β4 = K[M^3L^0T^−6 M^−4L^4T^8] = K

K = M^−1L^4T^2

K is not a dimensionless constant.