Question

It is 9th class question. Don't spam.​

Answer 1

Step-by-step explanation:

First. let's show the congruency of the 2 Δs......

GIVEN = QS bisects ∠PQR & ∠PSR.....

• In the 2 triangles, QS is common....
• As QS bisects ∠PQR, ∠PQS ( of the ΔPQS ) = ∠RQS ( of the ΔRQS )
• The same follows on the other side too........

So, through the ASA property, ΔPQS ≅ ΔRQS

Therefore, ∠P ≅ ∠R too.....

Answer 2

Step-by-step explanation:

Given:- QS is a angle bisector of angle PQR and PSR

to prove:-

• ∆PQS ≅ ∆QRS
• angle P = angle R

proof:-

$in \:∆PQS \: and \: ∆QRS$

QS is a angle bisector of angle PQR and PSR

ஃ angle PQS=SQR

angle PSQ=RSQ

QS is a common side.

By ASA criteria

∆PQS ≅ ∆QRS

BY CPCT angle P = angle R